Class 11MathematicsSequences and Seriesnth term of special series, Sum to n terms and Infinite number of terms
Difficultयदि $\left(\frac{1}{\alpha+1}+\frac{1}{\alpha+2}+\ldots+\frac{1}{\alpha+1012}\right) - \left(\frac{1}{2 \cdot 1}+\frac{1}{4 \cdot 3}+\frac{1}{6 \cdot 5}+\ldots+\frac{1}{2024 \cdot 2023}\right) = \frac{1}{2024}$,तो $\alpha$ का मान ज्ञात कीजिए।
- A$1367$
- B$1058$
- C$1056$
- D$1011$
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